Hmm...
{integral} 1/sinx dx
I got is ln tanx...
cos differentiate sinx is cos x and integrate 1/sinx would be ln sinx...
haha.... so eventually is (ln sinx)/(cos x) and thus ln tanx
XD.... I know it must be wrong.... but thats how I see it...
for {integral} 1/cosx dx
I thought will get (-ln cos x)/(sin x) ?
LOL...
cos differentiate cosx is -sin x.... how dya get 1-sinx??